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Mitsubishi Electric FX5 User Manual page 78

Melsec iq-f series
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Calculation example
This is a calculation example for the following communication settings and scan time when communicating with an inverter.
Communication speed = 19200[bps]
Length of 1 character = 10[bit]
Scan time = 10[ms]
■Calculation example 1
Calculation of required time when Pr. 3 is read by the IVRD instruction
Tinv=T
+T
+T
=181[ms]
1
2
3
T
=10[ms], T
=1[ms]
1
3
Calculate "T
" as follows because Pr.3 does not require change of the 2nd parameter.
2
T
= 2 × (T
+ T
) + T
2
4
5
Number of
send/receives
send/receive
1
T
= ( INT (
+1 ) × 10 ) + ( INT (
4
10
1
T
= INT (
+1 ) × 10 = 10 [ms]
5
10
T
[1]+T
7
T
[1] = ( INT (
6
T
[1] + T
[1] + T
7
8
T
[1] + T
[1] = ( (
7
9
T
[1] = 12 [ms]
8
T
[2]+T
7
T
[2] = ( INT (
6
T
[2] + T
[2] + T
7
8
T
[2] + T
[2] = ( (
7
9
T
[2] = 30 [ms]
8
Tinv = T
+ T
+ T
= 10 + 170 + 1 = 181 [ms]
1
2
3
■Calculation example 2
Calculation of required time when Pr.902 is read by the IVRD instruction
Tinv=T
+T
+T
=251[ms]
1
2
3
T
=10[ms], T
=1[ms]
1
3
Calculate "T
" as follows because Pr.902 does not require change of the 2nd parameter.
2
T
= 3 × (T
+T
) +
2
4
5
Number of
send/receives
send/receive
1
T
= ( INT (
+1 ) × 10 ) + ( INT (
4
10
1
T
= INT (
+1 ) × 10 = 10 [ms]
5
10
T
[1]+T
7
T
[1] = ( INT (
6
T
[1] + T
[1] + T
7
8
T
[1] + T
[1] = ( (
7
9
T
[1] = 12 [ms]
8
T
[2]+T
7
T
[2] = ( INT (
6
T
[2] + T
[2] + T
7
8
T
[2] + T
[2] = ( (
7
9
T
[2] = 12 [ms]
8
T
[3]+T
7
T
[3] = ( INT (
6
T
[3] + T
[3] + T
7
8
T
[3] + T
[3] = ( (
7
9
T
[3] = 30[ms]
8
Tinv = T
+ T
+ T
= 10 + 240 + 1 = 251 [ms]
1
2
3
4 INVERTER COMMUNICATION
76
4.4 Specifications
[1]
+
T
[2]
= 2 × (30 + 10) + 30 + 60 = 170 [ms]
6
6
The first
The second
send/receive
11
+1 ) × 10 ) = 30 [ms]
10
[1]+T
[1]
8
9
) +1 ) × 10 + ( INT (
10
[1] = 7.8 + 12 = 19.8 [ms]
9
1
) × (11+4) × 10 ) × 1000 = 7.8 [ms]
19200
[2]+T
[2]
8
9
) +1 ) × 10 + ( INT (
10
[2] = 10.4 + 30 = 40.4 [ms]
9
1
) × (9+11) × 10 ) × 1000 = 10.4 [ms]
19200
T
[1]
+
T
[2]
+
6
6
The first
The second
send/receive
11
+1 ) × 10 ) = 30 [ms]
10
[1]+T
[1]
8
9
) +1 ) × 10 + ( INT (
10
[1] = 7.8 + 12 = 19.8 [ms]
9
1
) × (11+4) × 10 ) × 1000 = 7.8 [ms]
19200
[2]+T
[2]
8
9
) +1 ) × 10 + ( INT (
10
[2] = 7.8 + 12 = 19.8 [ms]
9
1
) × (11+4) × 10 ) × 1000 = 7.8 [ms]
19200
[3]+T
[3]
8
9
) +1 ) × 10 + ( INT (
10
[3] = 10.4 + 30 = 40.4 [ms]
9
1
) × (9+11) × 10 ) × 1000 = 10.4 [ms]
19200
1
+1 ) × 10 ) = ( INT (
10
1
+1 ) × 10 ) = ( INT (
10
T
[3]
= 3 × (30+10) + 30 + 30 + 60 = 240 [ms]
6
The third
send/receive
1
+1 ) × 10 ) = ( INT (
10
1
+1 ) × 10 ) = ( INT (
10
1
+1 ) × 10 ) = ( INT (
10
19.8
+1 ) ×10 ) +10 = 30 [ms]
10
40.4
+1 ) ×10 ) +10 = 60 [ms]
10
19.8
+1 ) ×10 ) +10 = 30 [ms]
10
19.8
+1 ) ×10 ) + 10 = 30 [ms]
10
40.4
+1 ) ×10 +10 = 60 [ms]
10

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